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Simplify (3x^0y^7)(2x^2y)^3
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start by cubing everything on the left side what is 2^3?
i mean right side
2^3=8
yes, (x^2)^3 ?
that is x^6
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yes and (y)^3 ?
thats y^3
\[ (3x^0y^7)(2x^2y)^3= (3x^0y^7)(2^3x^{(2\times 3)}y^3)=(3x^0y^7)(8x^{6}y^3)\] \[=3\times 8x^{0+6}y^{7+3} =24x^{6}y^{10}\] is the required simplified form
yes, so you have (3x^0y^7)(8x^6y^3) now, just multiply
thanks both of you
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yw
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