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Mathematics 13 Online
OpenStudy (anonymous):

A. x = 24 sqrt 3, y = 8 B. x = 8, y = 24 sqrt 3 C. x = 24, y = 8 sqrt 3 D. x = 8 sqrt 3, y = 24

OpenStudy (anonymous):

OpenStudy (anonymous):

I am so confused. Thought I was on the right track with 16 sqrt 3= sqrt 2 times x 16 sqrt 3 - x sqrt 2 x= 16 sqrt 3/sqrt 2

OpenStudy (anonymous):

But then it doesnt make sense

OpenStudy (anonymous):

do you know what special triangle this is?

OpenStudy (anonymous):

no

OpenStudy (anonymous):

it's a 30-60-90 triangle... what makes this special is that the shortest side is always half of the hypotenuse. the other leg is always (shortest side) times (square root 3)...

OpenStudy (anonymous):

I was barking up the wrong tree completely. So I guess it would be C ????

OpenStudy (anonymous):

or perhaps I have it backwards?

OpenStudy (anonymous):

With the explanation ByteMe provided, I am thinking it is C ???? @ByteMe @Directrix

Directrix (directrix):

@Joshyface The 30-leg (shorter leg) is 1/2 the hypotenuse so the 30-leg is 1/2 of 16sqrt(3) = 8sqrt(3). Then, the 60-leg (longer leg) is sqrt(3) times the 30-leg. So, sqrt(3) times 8sqrt(3) = 3 * 8 = 24 which is what you thought all along.

OpenStudy (anonymous):

THANK YOU! I second guess myself even after I think I get it =(

Directrix (directrix):

Alrighty, then, @Joshyface Take a look at the attachments I posted above to help your refresh your memory on the 30-60-90 theorem.

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