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Mathematics 12 Online
OpenStudy (anonymous):

graph the solution to the following system of inequalities y<-2x+5 y>(or equal to) 2x+3

jimthompson5910 (jim_thompson5910):

let's tackle these graphs one at a time

jimthompson5910 (jim_thompson5910):

to graph y < -2x + 5, you follow these steps step 1) graph the line y = -2x + 5 step 2) make this line a dashed line step 3) shade below the dashed line

jimthompson5910 (jim_thompson5910):

the line is dashed because we are NOT including the boundary line (because we don't have an "or equal to" as part of the inequality sign)

jimthompson5910 (jim_thompson5910):

you shade below the line because it's a "less than" and y is fully isolated

OpenStudy (anonymous):

ok i have got that part done

jimthompson5910 (jim_thompson5910):

you repeat for the second graph as well

jimthompson5910 (jim_thompson5910):

however, this time the boundary line will be solid and you will shade above the line

jimthompson5910 (jim_thompson5910):

the final solution set will be where the two shaded regions overlap

OpenStudy (anonymous):

when you say above the line do you mean / to the left of the line

jimthompson5910 (jim_thompson5910):

by above the line, i mean that if the line isn't completely vertical, you can shade points that lie above it ie start on any point on the line and go straight up (and shade everywhere that's above the line)

jimthompson5910 (jim_thompson5910):

ex: here is a line |dw:1374128062467:dw|

jimthompson5910 (jim_thompson5910):

pick any point on it |dw:1374128079339:dw|

jimthompson5910 (jim_thompson5910):

then go straight up |dw:1374128092033:dw|

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