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Mathematics 9 Online
OpenStudy (anonymous):

please help!! 1 medal and fan In parallelogram DEFG, DH = x + 5, HF = 2y, GH = 3x – 1, and HE = 5y + 4. Find the values of x and y. a. x = 35, y = 20 b. x = 21, y = 20 c. x = 20, y = 35 d. x = 21, y = 37 https://rialto5819-ehs-pps.gradpoint.com/Resource/2146263,72F,0,0,0,0,0/Assets/testitemimages/geometry_a/quadrilaterals/mc034-1.jpg

OpenStudy (whpalmer4):

What do you know about the diagonals of parallelograms?

OpenStudy (whpalmer4):

Yes, that's right — the diagonals bisect each other. DH = HF GH = HE Therefore you can write the following equations: \[x+5 = 2y\]\[3x-1=5y+4\] Rearrange the first equation to give \(x\) in terms of \(y\). Substitute that expression for \(x\) in the other equation, and solve for \(y\). Use the value of \(y\) to find the value of \(x\) in either equation.

OpenStudy (anonymous):

ok i get it

OpenStudy (anonymous):

thank you

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