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Physics 16 Online
OpenStudy (anonymous):

A police car moving at 140 km/hr chases a speeding car at 110 km/hr. How much closer to the speeding car does the police car get each time??

OpenStudy (souvik):

do u know relative velocity...?

OpenStudy (anonymous):

no :(

OpenStudy (souvik):

a simple example....when u are going by bus or train..u see the trees or buildings beside the road moving backward...

OpenStudy (anonymous):

yes. then?

OpenStudy (shamim):

if u r going by a bus 10 km/h and a track is going by 7 km/ h along the same way

OpenStudy (shamim):

then ur relative velicity with respect to that track will b 3 km/h

OpenStudy (souvik):

mathematically, when u calculating someones motion relative to you ...then you have to subtract your velocity from the velocity of someone using vector rules...

OpenStudy (shamim):

can i say more example for ur better understanding

OpenStudy (anonymous):

So, 140km/hr - 110km/hr That makes 30km/hr?

OpenStudy (souvik):

yes..the police car is coming towards the speeding car with a velocity of 30km/hr

OpenStudy (anonymous):

do i have to divide 30km/hr by 60 mins?

OpenStudy (souvik):

yes...do that and convert km to meter

OpenStudy (anonymous):

so, the police car gets 0.50km/min

OpenStudy (anonymous):

Thank you Souvik and Shamim! :)

OpenStudy (souvik):

you are welcome..:)

OpenStudy (shamim):

welcome

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