what is the slope-intercept: equation of the line that passes through the point (6, 4) and is parallel to y = 1/3 x - 3. help me find the answer or the procedure pls
Well when you have the equation of one line and you want a parrllel lin the slope is going to be the same for both equations. then use the equation y-y1=m(x-x1) to find the anwer. if you post your answer when you get it I'll check it for you.
so i have to plot the x & y-intercept in the equation but i still dont get how
let me show you how to find your new equation. so the formula we are going to use to find the ne equation is y-y1=m(x-x1) our slope (m) is the same as the equation givin. so the slope is 1/3 then we are given the point (6,4) this will be what we put in the place of y1 and x1 remember that 6 is x1 and 4 is y1 this time. so y-4=1/3(x-6) now you are going to muliply 1/3 to x and then 1/3 to 6 you should get y-4=1/3x-2 your last step is to add 4 to both sides so that you get 1 by itself. your final answer should be y=1/3x+2
does that make sense?
oh ok so the equation to find the slope-intercept is y-y1=m(x-x1) right?
only when you have the slope and at least one set of ordered pairs
oh ok then thank you very much
you're welcome
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