Question

Solve for x.

log2(7x + 1) = log2(2 - x)


a) 1/8

b) 8

c) 1/4

d) 4

Answer 1

7x + 1 = 2 - x
solve for x

Answer 2

Since the two logs are to the same base and there are no other terms, the expressions inside the logarithms must be equal. So, we can take 2 and raise it to the power of each side to get:
\[7x+1=2-x\]From here you can solve for x.

Answer 3

7x+1=2-x
-1 -1
7x=1-x
+x +x
7x^2=1
x^2=1/7

im so confused !??

Answer 4

7x + x = 8x

Answer 5

Simply take antilog on base 2 on both sides and you will get what RadEn posted in the first reply.