@Nurali
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lazy.
?i just want help..
everything on top matches everything on the bottom so it would be 1 since all the veriables cancel and all numbers devided by theselves equal 1
im confused
@divagirl421 They all will be cancelled out.
i dont add anything?
No because the above values are same.
Right. since every value cancles itself out ther is no need to add. if you brake the problem in to pieces you will see.
id stack the stuff top to bottom and line up like terms to avoid the confusion
no sorry i didnt explain properly the repeating one on the bottom is just there to type the answer next to it
Hopefully this is the answer: 9x3y2 + -4x3y2 = 5x3y2-6xy + -4xy2 + 5x3y2 + 2x3y3 + -5x4y3
oh ok. then let me look at it again
yea im sorry
@divagirl421 Did this answer help you?
\[\Large -5x^4y^3~~~~~~~~~~~~~~+9x^3y^2-4xy^2\\\Large ~~~~~~~~~~~~~+2x^3y^3-4x^3y^2~~~~~~~~~~~~-6xy\\------------------------\]
idk im still learning this
since they are lined up by "like terms" just add down the columns
(-5x^4y^3+9x^3y^2-4xy^)+(2x^3y^3-4x^3y^2-6xy) combine the negitives in each set of parentheses first to make it easier.
like -5 and -6?
(-5x^4y^3-4xy^2)+(-4x^3y^2-6xy) (-9x^5y^5)+(-10x^4y^3)
oooo i see what you did
then we will add the positives to the positives and the negitives to the negitives (-5x^4y^3+9x^3y^2-4xy^2)+(2x^3y^3-4x^3y^2-6xy) (-9x^5y^5)+(-10x^4y^3) (-9x^5y^5+9x^3y^2)+(2x^3y^3-10x^4y^3) +9x^3y^2+2x^3y^3-9x^5y^5-10x^4y^3
9x^3y^2+2x^3y^3-9x^5y^5-10x^4y^3 11x^6y^5-19x^10y^8 then combine the last bit of the equation -8x^16y^13
wow thats it?
Yep all you were doing was combining like terms and since none of the exponets were negative you add them together and the do adding and subtration for the numbers
wow thank you alot that was a good explanation
You're welcome
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