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Mathematics 11 Online
OpenStudy (anonymous):

What is the slope of the line? https://media.glynlyon.com/g_alg01_2012/3/83b.gif

OpenStudy (anonymous):

1

OpenStudy (anonymous):

it's run is 1 and it's rise is 1

OpenStudy (anonymous):

1/1 =1

OpenStudy (anonymous):

Alright thanks peasant!

OpenStudy (anonymous):

Anytime! :D

OpenStudy (anonymous):

hey peasant

OpenStudy (anonymous):

Yes?

OpenStudy (anonymous):

what is general form?

OpenStudy (anonymous):

I think you mean this general form of a linear equation: ax + by + c = 0.

OpenStudy (anonymous):

yea like what would be the general form of the same line https://media.glynlyon.com/g_alg01_2012/3/83b.gif

OpenStudy (anonymous):

What's the equation of the line?

OpenStudy (anonymous):

It doesn't give me an overall equation. Just the awnsers -x + y - 2 = 0 x + y - 2 = 0 2x + y - 2 = 0

OpenStudy (anonymous):

\[slope=\frac{ 0-2 }{2-0 }=\frac{ -2 }{ 2}=-1\]

OpenStudy (anonymous):

We got slope down. ;)

OpenStudy (anonymous):

But zach, I'm not sure how to do this one... @surjithayer got anything?

OpenStudy (anonymous):

|dw:1374179888987:dw|

OpenStudy (anonymous):

Im taking an online course and a lot of the questions are messed up

OpenStudy (anonymous):

\[slope=\frac{ y2-y1 }{x2-x1 }\]

OpenStudy (anonymous):

hm

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