The area of a rectangular pool is 48 square meters. The length is three times as long as the width. What are the dimensions of the pool?
A. 2 and 24
B. 3 and 16
C. 4 and 12
D. 6 and 8

Question

The area of a rectangular pool is 48 square meters. The length is three times as long as the width. What are the dimensions of the pool?
	A.	2 and 24
	B.	3 and 16
	C.	4 and 12
	D.	6 and 8

johnweldon1993 · Answer

We know that area = length * width

$$A = L \times W$$

We also know that the length is 3 times the width so

$$L = 3W$$

So we can substitute that into the first equation for 'L' along with 48 for the area

$$48 = 3W \times W$$

$$\large 3W^2 = 48$$

Can you solve this?

anonymous · Answer

no :/

johnweldon1993 · Answer

Its okay don't get down on yourself for it

$$\large 3W^2 = 48$$

We first want to divide both sides by 3 to isolate W²

$$\large W^2 = 16$$

Now take the square root of both sides to solve for W

$$W = \sqrt{16}$$

W = ..?

anonymous · Answer

i get it now (:

johnweldon1993 · Answer

Awesome!

johnweldon1993 · Answer

So thats the width and whats the length?

anonymous · Answer

8

johnweldon1993 · Answer

Not quite...if we find that

W = √16
W = 4

And the length is 3 times that number we have

W = 4
L = 12