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cuberoot(x-2) +7 =28
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\[\sqrt[3]{x-2} +7=28\]
First you must get the radical by itself
soo \[\sqrt[3]{x-2}\] = 21
precisely, then the oppoite of cbrt-ing is ....?
would you cube it or square it?
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cube it, since we're dealing with cbrt, rememebr like goes with like
21 cubed is 9,261
so x-2 = 9,216
then get x by itself
add 2.. so x=9,218
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Alright now plug it back in to your original equation and see if both sides match up.
yeah, it does but its not an answer choice
lol.. is 9263 a choice?
Sorry, my bad, and thats weird, whata re the choices?
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