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Find the zeros of the polynomial function and state the multiplicity of each. f(x)=(x^2-4x+4)(x^2+14x+49)
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First I would either expand out your brackets [but I find this creates more confusions] or merely factorise them You should end up with four brackets of the form (x+a)(x+b)(x+c)(x+d) [this is not saying that all the integers are positive and different] Then the mulitplicity is how many times a solutions appears e.g. (x-2)(x-2)(x+3) The multiplicity of '2' would be 2 The multiplicity of '-3' would be 1 Hope this helps!
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