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The 48th term in the sequence 6, 13, 20, 27, ... is ??
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first term is \(6\) second term is \(6 + 7\) third term is \(6 + 7 + 7 = 6+2\times 7\) fourth term is \(6+3\times 7\)
48th term is \(6+47\times 7\)
you could also use the formula
yes, and the formula will give \(6+47\times 7\)
what is the formula? and do i go ahead and find solve that? would my answer be 335?
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an = a1 + (n-1) * d
i think the formula is \(a_1+(n-1)d\) which in this case is \(6+47\times 7\)
and yes, 335 is right
n = the number of the term you want to find a1 = the first number d = the common difference
it comes out the way satellite said
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i think i understand it now. Thank you guys so much!
YW :)
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