W^2 + 30w + 81 factor using gcf 21 and 3. Show work
actually it factors as \((w+3)(w+27)\) but i am not sure what that has to do with 21 in any case 2 and 21 are not greatest common factors of anything here
I thought I hit 27 I don't know how that became a 21 but that's what I meant and the 2 is the exponent
3 and 27 is what I meant and this is giving me a headache I might just take a zero because I don't get it
Try to factor by finding its GCF... First, look at the all of the coefficients and constants, in particular, the:1, 30, and 81. The GCF of these numbers is 1. This means nothing can be evenly divided (factored) out of each coefficient and/or constant term. Now, try to find the GCF of the variables.It will be a term containing variables with the largest exponents that will evenly divide out of each term. The GCF for the variables is 1, meaning no variables can be evenly factored out of this polynomial. Now, try to find the GCF of any functions (like sin or cos). This polynomial does not contain any functions that can be factored out. This polynomial cannot be factored using the GCF method.
Join our real-time social learning platform and learn together with your friends!