How do you simplify this?
\[\sqrt{125}\]
@whpalmer4 @whydoihavetosignupl @EffImHighOffSkittles @eaileen @R00nnYBraiNsbiG @terenzreignz @uri @IloveYou* @primeralph @prettyboy20202 @ajprincess @AnElephant @SnuggieLad @snorl4x @Directrix @dan815 @divagirl421 @DarkKat @Dmitt @faix95 @GOODMAN @hobbs978 @jhonyy9 @Jack17 @KawasumiKimiko @Luigi0210 @Loujoelou @love_jessika15 @lkkk @Callisto @countonme123 @ChrisJP @nincompoop @mukushla @marylou004 @mlb004 @MissHN182 @thefon19 @ryanjnfish @ladycomical @DDCamp @ryanjnfish @jd1028 @phantomofthemathwork @jtrich13 @ajprincess @PaulaCamacho @laxman03 @beccabee77 @babyslapmafro @whpalmer4 @jtrich13
$$5\sqrt{5}$$
you asked this same question samuel
whats your teamwork at?
52 -.-
did it increases?
by 2 but seriously how do u solve tht
$$125=5^3=5^2\times5$$
$$\sqrt{5^2\times5}=\sqrt{5^2}\sqrt{5}=5\sqrt5$$
ohhh thx
The key is to factor out the integer inside the root, and then use the completely multiplictive property of $$\sqrt{x}$$
Join our real-time social learning platform and learn together with your friends!