could someone please help with 4 of my questions? im not sure what im doing incorrectly! :(
Write the equation of the line that is parallel to the line y = 2x + 2 and passes through the point (5, 3). y = 2x − 7 y = −x − 2 y = 2x − 2 y = −x − 7 2. Write the equation of the line that is perpendicular to the line y = 2x + 2 and passes through the point (6, 3). y = 2x + 6 y = −x + 3 y = −x + 6 y = 2x + 3 3. Write the equation of the line that is parallel to the line 3x − y = −3 and passes through the point (4, −2). y = −x − 6 y = −x − 14 y = 3x − 6 y = 3x − 14 4. Write the equation of the line that is perpendicular to the line 2x − 3y = 3 and passes through the point (−8, 2). y = x − 10 y = x + 10 y = −x − 10 y = −x + 10
please ask one at a time
I'll help with the first one
y = 2x + 2 has a slope of 2 anything parallel to this will also have a slope of 2
ok
so m = 2 y = mx + b y = 2x + b .. plug in the slope m = 2 3 = 2(5) + b ... plug in the point the line goes through, (5,3) 3 = 10 + b 3 - 10 = b -7 = b b = - 7 so we know m = 2 and b = -7
which means the parallel line is y = 2x - 7
thank you for the first one :) i see what i did wrong on that one
hopefully that will help you with the rest if not, then let me know
im still having a bit of trouble :/ sorry
its ok
the slope of y = 2x + 2 is m = 2 flip the fraction and flip the sign to get m = -1/2
so the slope of the perpendicular line is m = -1/2
ok got that part
y = mx + b y = (-1/2)x + b 3 = (-1/2)*6 + b solve for b
what do you get when you do?
got -36?
hmm a bit off
3 = (-1/2)*6 + b 3 = -6/2 + b 3 = -3 + b b = ??
-1?
no you have to add 3 to both sides now
lol sorry... 6?
good
so the equation is y = -1/2x + 6
ughh... i totally dont get these... there so hard for me.. idk why!
keep at it and hopefully things will click better
only have 3 more then im down... ; p
try the next one and tell me what you get
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