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15 le 3/4(f+4)
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\[15\leq \frac{3}{4}(f+4)\] multiply both sides by \(\frac{4}{3}\) to get \[15\times \frac{4}{3}\leq f+4\]
what is \(15\times \frac{4}{3}\) ?
20?
yes 3 goes in to 15 5 times, and 5 times 4 is 20
so now we are looking at \[20\leq f+4\] solve by subtracting 4 from both sides what do you get ?
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16, do I flip the signs?
no not when you subtract only flip if you multiply or divide by a negative numbers
final answer should look like \(16\leq f\)
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