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Mathematics 26 Online
OpenStudy (anonymous):

What is the reflection image of P(0, 0) after two reflections, first across x = -3 and then across y = 4? A. (4, -3) B. (-6, 8) C. (4, -6) D. (-8, -6)

OpenStudy (anonymous):

OpenStudy (sumi29):

Ok, so lets start by shifting the point P about x=-3 line. Its distance from x=-3 is 3 units to the right. So when I reflect it about x=-3, its new distance will still be 3 units, but in the opposite direction of the x=-3 line. So whats the new x co-ordinate of P?

OpenStudy (anonymous):

im still kind of confused. would it be (0, -3)?

OpenStudy (sumi29):

Ok first of all, only the x co-ordinate would change, not the Y. So your answer is wrong. Secondly, look at it this way: Think of the x =-3 line as a mirror. Now a point on the right side of this mirror....where does it appear on the left side of the mirror? Remember, the distance will be same, only the direction will change.

OpenStudy (anonymous):

so it would be (-3,0)?

OpenStudy (sumi29):

Correct! So you have the answer for the first reflection. Similarly, now consider the y=4 line as the mirror. Now where would the point appear? This time, its X co-ordinate remains the same, only the Y changes. Remember: same distance!!

OpenStudy (anonymous):

okokok

OpenStudy (sumi29):

Actually, you don't even need to bother with finding that out. The only option with -6 as the x co-ordinate is A, so thats the answer.

OpenStudy (anonymous):

oh ok. thank you :)

OpenStudy (sumi29):

Welcome!!! What course is this btw?

OpenStudy (anonymous):

geometry

OpenStudy (sumi29):

LOL that I am aware of. I am asking which grade?

OpenStudy (anonymous):

HAHAHAHA oh it was supposed to be a sophomore class. but i never took it.

OpenStudy (sumi29):

Cool...no problems, you are getting the hang of it. You should be able to ace this soon!

OpenStudy (anonymous):

awe, thank you :)

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