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1. Let f(x) = 3x – 5. Find its inverse represented by the function notation f^ –1(x).
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what would you do if you had to solve \[3x-5=17\]?
first you would add 5 to both sides, which would give you 3x= 22 and then you would divide 3 on both sides?
yes and that is what the inverse does add 5, divide by 3 \[f^{-1}(x)=\frac{x+5}{3}\]
thats it?
yes that is it
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oh cool, thanks! Could you help me with another question?
you could write \[x=3y-5\] and sovle for \(y\) to get \[x+5=3y\] \[y=\frac{x+5}{3}\] but some times you can do it in your head
is it y or f^-1(x)?
\(f^{-1}\)
okay, thanks!!
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