Question

PLEASE HELP:In the below system, solve for y in the first equation.

x – 3y = –6
2x – 7y = 10
I got y=-22 but the answers are one thirdx + 2

negative one thirdx + 6

–x + 2

negative one thirdx + 2

Answer 1

your correct :)

Answer 2

but its not one of the choices :/ thats whhy im confused

Answer 3

what are the choices?

Answer 4

1/3x+2
-1/3x+6
-x+2
-1/3x+2

Answer 5

would it be 1/3x+2?

Answer 6

I think so too

Answer 7

Im going to put that I dont see how it could be anything else

Answer 8

Let's use the first equation and subtract x from both sides

Answer 9

x-3y=6
3y=6−x
y=6−x/3

Answer 10

x-3y=-6
x+6=3y
3y=x+6
\[y=\frac{ 1 }{3}\left( x+6 \right)=\frac{ 1 }{3 }x+2\]