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Mathematics 7 Online
OpenStudy (anonymous):

https://pwnd9373-ndscholarship-ccl.gradpoint.com/Resource/630568,72F,0,0,0,0,0/Assets/testitemimages/geometry_b/circles/mc036-1.jpg What is the value of x to the nearest tenth?

OpenStudy (anonymous):

@whpalmer4 @primeralph @mathstudent55 helllllpp

OpenStudy (whpalmer4):

|dw:1374261700390:dw|

OpenStudy (whpalmer4):

|dw:1374261758383:dw|

OpenStudy (whpalmer4):

Use the Pythagorean theorem to find the radius

OpenStudy (anonymous):

so do i do 24=6x and then do 24/6=6x/6 which=4

OpenStudy (whpalmer4):

\[r = x\]

OpenStudy (whpalmer4):

no, you do \[r^2 = 6^2+12^2\]

OpenStudy (whpalmer4):

because that line from the center to the chord is perpendicular, it bisects it, giving you 12 as the base of the triangle, 6 as the height, and r as the hypotenuse.

OpenStudy (anonymous):

the answer is12

OpenStudy (whpalmer4):

Whose answer is 12?

OpenStudy (anonymous):

these are the answer choices 5.5 4.9 12.0 13.4

OpenStudy (whpalmer4):

Well, obviously it isn't one of the first 2, because 6 doesn't even go from the center to the edge, right? 12 is a a trap answer. \[r^2 = 6^2+12^2 = 36 + 144 = 180\]\[r = \sqrt{180} = \sqrt{9*20} = 3\sqrt{20} = 3\sqrt{4*5} = 3*\sqrt{4}*\sqrt{5} = 6\sqrt{5}\]\[\sqrt{5} \approx 2.236\]\[6\sqrt{5}\approx 13.4\]

OpenStudy (anonymous):

The plane is vertical. What best describes the shape of the cross section?

OpenStudy (whpalmer4):

My preference is one question per post, thanks. Also, I prefer helping people who give out medals when they get help! Looks like |dw:1374263063531:dw|

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