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Write two linear equations you can use to graph the equation. y=|3/2x+6|+3
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I will give medal
Ok, so, y=|3/2x+6|+3. That means that \[y = \pm(\frac{ 3 }{ 2 }x + 6) + 3\]. Now solving each of these equations, one for the plus and one for the minus, what do we get?
???
The absolute value of 3/2x + 6 is required, so it could be positive or negative.
kk
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??
so it can be negative and positive bcz the absolute valuse
I've got to go, but you are in good hands with zzr0ck3r :)
kk
y = |x| implies y=x or y=-x so you have y=|3/2x+6|+3 y-3 = |3/2x+6| so (y-3) = 3/2x+6 and -(y-3) = 3/2x+6 solve for y in each of these equations.
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so slve for y
*solve
im lost
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