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y varies inversely as twice x. When x = 3, y = 8. Find y when x = 2.
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when something "varies inversely" to something means it has a relationship to the inverse of that something inverse of something is 1/something
so "y" varies inversely to "x" would be y = "n"/x "y" varies inversely to "x" would be y = "n"/2x now we don't know what the "n" value is but we know that when -> When x = 3, y = 8 so \(\bf y = \cfrac{n}{2x}\\ \text{When x = 3, y = 8 }\\ 8 = \cfrac{n}{2(3)}\) then just solve for "n" to find "n" :) once you get "n", the plug it in and, when x=2 \(\bf y = \cfrac{n}{2(2)}\)
"y" varies inversely to "2x" would be y = "n"/2x I meant :/ so much for my pasting hehe
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