Question

can someone help me with the steps factoring
-6y^2+53y+9

Answer 1

When factored it'll look like this: -(y-9) (6 y+1)

Answer 2

ok can you help me with the steps please

Answer 3

Using,

http://upload.wikimedia.org/wikipedia/commons/thumb/3/3d/Completing_the_square.ogv/400px--Completing_the_square.ogv.jpg

with a=-6, b=53 and c = 9
a(y + b/2a)^2 + c - (b/2a)^2 = -6y^2+53y+9
-6(y +53/2(-6))^2 + 9 - (53/2*(-6))^2
That's it!

Answer 4

Okay. So first you'd look for something that can be used with (-6) and 9.

So it'd be: -6y^2 - 54y +1y +9

=(-6y^2 - 54y) + (1y + 9)
Common factor from each bracket and it results in:

=-6y(y+9) +1 (y+9)
=(-6y + 1) (y+9)

Answer 5

ok thank you