Help Please! (: Consider the function f(x) = 8 (x - 4)^{2/3}. For this function there are two important intervals: (negative infty, A) and (A,infty) where A is a critical number. Find A.
take the derivative, set it equal to zero and solve
ok that was silly, the derivative does not have any zeros however, it is undefined at \(x=4\)
Yeah I did the same. the derivative has no zeros so would A = 4? @satellite73
@loser66
what do you want me to do? want to see math tool's answer? there you go: https://www.wolframalpha.com/input/?i=%288%28x-4%29^%282%2F3%29%29%27
don't forget, critical point can be a saddle point or a point the graph "jumps", no need to be the points f(x) turns from decrease to increase or vice versa. In this case, it's 4
Ohhhh. okay. I understand it a bit more now (: thanks!
yw
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