Simplify root(75x^2y^-4)
a. (5root3)x/y^2 or b. (5root3)|x|/y^2
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jhonyy9 (jhonyy9):
so first ,,root" there mean squarroot ?
jhonyy9 (jhonyy9):
hope that yes
so than will try it step by step
how you can rewriting 75 using square of a number ?
jhonyy9 (jhonyy9):
you dont like cooperate anything ?
jhonyy9 (jhonyy9):
75 = 3*5^2
ok ?
jhonyy9 (jhonyy9):
75x^2y^-4
do you can rewrite it using just positive exponent ?
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jhonyy9 (jhonyy9):
so y^(-4) = 1/(y^4)
yes ?
OpenStudy (anonymous):
Oh my, so sorry, I went out! I'm back now though.
I solved it out:
\[\sqrt{75x^{2}y^{-4}}\]
\[\sqrt{75} = 5\sqrt{3} \]
\[\sqrt{x^2} = x\]
\[\sqrt{y^-4} = \frac{ 1 }{ y^2 }\]
jhonyy9 (jhonyy9):
ok
yw
OpenStudy (anonymous):
But this would be: \[\frac{ 5 \sqrt{3}x }{ y^2 }\]
Is it possible for it to be: \[\frac{ 5 \sqrt{3}|x| }{ y^2 }\]
jhonyy9 (jhonyy9):
a. is right because
root(75x^2y^-4) = sqrt((3*5^2 *x^2)/y^4) = (5xsqrt3)/y^2
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