Question

MEDAL AWARD Help !! Find the equation of a line in slope-intercept form that passes through the points (-2, 20) and (3, -10).

Answer 1

first you need the slope

Answer 2

m = (y2-y1)/(x2-x1)


m = ( -10- 20)/(3-(-2))


m = ( -10- 20)/(3+2)


m = (-30)/5


m = -6


So the slope is m = -6

Answer 3

your supposed to find the equation ?

Answer 4

I know, you use that slope to do so

Answer 5

how do u do that ?

Answer 6

by using y = mx+b

Answer 7

plug in m and (x,y) = (-2,20)

Answer 8

*plug in m = -6

Answer 9

-6(3,-10)=(-2,20)

Answer 10

y = mx+b

y = -6x+b

20 = -6(-2) + b

solve for b

Answer 11

i got 12 then you divide by 20 ??

Answer 12

no

Answer 13

20 = 12 + b

20 = b + 12

b = ??

Answer 14

8 ..?

Answer 15

correct

Answer 16

so the equation is y = -6x + 8

Answer 17

thanks

Answer 18

np