Question

what is the slope of a line that is perpendicular to the line represented by the equation 3x+4y=12 ???

Answer 1

your first task is to isolate y

Answer 2

3x+4y=12

3x+4y-3x = 12 - 3x

4y = -3x + 12

y = -3x/4 + 12/4

y = (-3/4)x + 3

This last equation is in the form y = mx+b where

m = -3/4
b = 3

Answer 3

So the slope of y = (-3/4)x + 3 and 3x+4y=12 is m = -3/4

Answer 4

to find the slope of any perpendicular line to this one, you simply flip the fraction and flip the sign


flip the fraction: -3/4 -----> -4/3

flip the sign: -4/3 -----> +4/3 or just 4/3


So the slope of any perpendicular line to 3x+4y=12 is 4/3

Answer 5

slope of the line ax+by=c is given by -(coeifficient of x/coefficient of y)

Answer 6

thanks!

Answer 7

yw