Question

In the diagram below, AE = 6, EB = 3, and DE = 2. Find CE.

A. 6
B. 3
C. 8
D. 9

Answer 1

sooo how do i solve this?

Answer 2

use the intersecting chords theorem, explained here

http://www.mathopenref.com/chordsintersecting.html

we can say

AE*EB = CE*DE

Answer 3

i still dont get it help please!

Answer 4

always remember this theorem which is named as :
\[\huge Intersecting~Chord~Theorem\]

Suppose this is a circle,

In this, AB and CD are chords of a circle and E is the centre of the circle

So this theorem states that:
\[\huge AE \times EB=CE \times ED\]