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Mathematics 17 Online
OpenStudy (anonymous):

how to take k +1 common in k3+18k2+3k+2

OpenStudy (harsimran_hs4):

k^3 + k^2 + 17k^2 + 17k -14k -14 + 16 k^2(k+1) + 17k(k+1) -14(k+1) + 16 (k+1)(k^2 + 17k - 14) + 16 so in case you are looking for k+1 to be one of the factors you cannot

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