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Mathematics 7 Online
OpenStudy (anonymous):

The graph below is represented by which system of inequalities? going to post picture. Answers ; -x + 3y < 9 y > -2x + 1 -x + 3y less than or greater to 9 y > -2x + 1 -x + 3y < 9 y greater than or equal to -2x + 1 None of these systems represent the graph shown.

OpenStudy (anonymous):

OpenStudy (anonymous):

ok let me see

OpenStudy (anonymous):

alrighty. :)

hartnn (hartnn):

can you first find the equation of those 2 lines?

OpenStudy (anonymous):

why is the second set -x+3y less than or greater to??

OpenStudy (anonymous):

you need to first solve for y in the first equation in 1st set

OpenStudy (anonymous):

Okay , hold on. 1 ) -x+3y <9 +x +x ----------- = 3y < 9x / 3 / 3 y < 3x would you solve it like that ? or another way. i'm a bit confused about that.

OpenStudy (anonymous):

ok so it would actually be y<1/3x +3 wouldn't it??

OpenStudy (anonymous):

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OpenStudy (anonymous):

Ohhhhh. I'm seeing the vision.

OpenStudy (anonymous):

yea

OpenStudy (anonymous):

do u kinda get it or...

OpenStudy (anonymous):

I kind of get it , but 'm getting there. It's the graph & corresponding them with the answers.I don't get.

OpenStudy (anonymous):

oh ok. well in the first set, the two equations: one would have a y-intercept at 3 and the other @ 1. pretty sure u knew that

OpenStudy (anonymous):

Indeed , I did.

OpenStudy (anonymous):

:(

OpenStudy (anonymous):

wish I could be of more help--- what do u specifically not understand?

OpenStudy (anonymous):

ok I think that we can definitely eliminate the 3rd set right?

OpenStudy (anonymous):

wait nvm

OpenStudy (anonymous):

No. It's fine.

OpenStudy (anonymous):

Sorry for being an inconvience. I just don't get it.

OpenStudy (anonymous):

its alright. u know all abt the shading of inequalities right?

OpenStudy (anonymous):

No , not really.

OpenStudy (anonymous):

oh well that has kind of a big part in inequalitites

OpenStudy (anonymous):

lets say if u wanna check if an equality is true, u can choose any point on the graph(preferably 0,0) and if if it works in the inequality then u shade according to that

OpenStudy (anonymous):

okay , so can I just plug in zero for each one ? To get the answer or a pont that's on the graph and plug it in ?

OpenStudy (anonymous):

wait I don't get ur second set of linear equalities. why is one of them less than or greater to. u meant or equal to right?

OpenStudy (anonymous):

less than or equal to , sorry for that.

OpenStudy (anonymous):

oh ok that's fine :)

OpenStudy (anonymous):

okay. i'm still confused. never mind. thank you for your time. :) Sorry for the waste of time.

OpenStudy (anonymous):

i feel really bad now. its kinda hard to explain like online or like when ur reading off something

OpenStudy (anonymous):

like for me i learn when someone is next to me showing me how to do it and explaining... :(

OpenStudy (anonymous):

im so sorry :(

OpenStudy (anonymous):

i thought it was the 1st set though

OpenStudy (anonymous):

It's okay. I passed the test with a 100 % so you did help.

OpenStudy (anonymous):

yay!!! :) & no i didn't help

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