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Write the equation of the line that passes through (2, 5) with a slope of 3 in point-slope form.
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The formula you'll want to use here is: \[y-y_1=m(x-x_1)\]where m is the slope, and x_1,y_1 are the coordinates of any point on the line. You have the slope, and a point, so you have everything you need to plug into this equation. Then you can simplify if you need.
y – 5 = 3(x – 2)
?
@topstryker The point-slope form of the line is y-y1=m(x-x1) Substitute the coordinate values from the given point and the given slope value y-5=3(x-2)
you got it @topstryker
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