https://pusd4237-phoenixunionhs-ccl.gradpoint.com/Resource/1726005,72F,0,0,0,0,0/Assets/testitemimages/geometry_a/similarity/mc078-1.jpg When ya look at that pic, how do you find Y? How do you find X?
Use this theorem: The measure of the altitude drawn from the vertex of the right angle of a right triangle to its hypotenuse is the geometric mean between the measures of the two segments of the hypotenuse.
What's a geometric mean?
Is it just a fancy way to say mean between hypotenuse X, 4, 12?
yes
So the geometric mean of the numbers in this problem = Y?
geometric mean of a and b, if they are two real numbers is \[\Large \sqrt{a \times b}\]
And that = Y?
Nope, you have to use pythagoreans theorme to fin that value
\[\frac{12}{y}=\frac{y}{4}\]
\[y^2=48\]
\[y=4\sqrt{3}\]
Now use the Pythagorean Theorem to find x
Ok, but what were those first two comments for in the problem?
* Mertsj?
I'm not sure what you are referring to.
12/y=y/4-who, what where when why how? :(
That's what the theorem means when it says that the altitude to the hypotenuse is the geometric mean of the segments of the hypotenuse.
Oh, oh! Got it! Thanks!
yw
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