Question

What is the equation of a parabola with a vertex at (0, 0) and a focus at (0, 6)

Answer 1

the equation is
x^2 = 4py

Answer 2

p is te focus in this case is p=6

Answer 3

x^2=4(6xy)?

Answer 4

yes it is but let me graph to make sure

Answer 5

x^2=4(6xy)
u must remove the x inside the parentesis
x^2 = 24y

Answer 6

Thank you!^^