Question

PLEASE HELPPP. I have no idea how to do this. log(10^3x^7)
A.21log(x)
B.3x^7
C.21
D.3+7log(x)

Answer 1

remember that the log of a product is equal to the sum of the logs of the multiplicands

Answer 2

@julian25 why did you delete? that was good stuff

Answer 3

yes but i saw u telling me
dont give the answer.........

Answer 4

I honestly have no idea how to do this, or any idea with logs because I am taking an online program and have no base of trig/precal. First time taking it.): If you could please teach me.

Answer 5

first you use the rule that log(A*B) = log(A) + log(B)

Answer 6

so that will break

log(10^3x^7)

into

log(10^3) + log(x^7)

Answer 7

what is your next move?

Answer 8

Do you just simply add them?

Answer 9

what do you mean by that

Answer 10

Wait is the answer 3x^7?

Answer 11

what does log(10^3) simplify into

Answer 12

3

Answer 13

keep in mind that this log is by default base 10

Answer 14

good

Answer 15

so

log(10^3) + log(x^7)

becomes

3 + log(x^7)

Answer 16

how would you simplify log(x^7)

Answer 17

I just put it into my calculator right now aha, and got 7.But how do you do it without a calculator?

Answer 18

well you use the rule that log(x^y) = y*log(x)

Answer 19

that will bring down the exponent

so log(x^7) = 7*log(x)

Answer 20

so in the end, the final answer is


3 + 7*log(x)

Answer 21

I understand now! Thank you so much for the help! (:

Answer 22

yw