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Simplify 5x^2-19x-4/x-4 will give medal
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first factor the numerator 5x^2 - 19x -4
it ill look like (5x +/- a)(x +/- b) can you figure out the a and b and correct signs
hopefully one factor will be (x - 4) so we can simplify
lets suppose it is x - 4 then we have (5x +/- a)( x - 4) now +/- a will be equal to +1 to get the -4 in the original expression but will that give us the -19x?
if so then we got it
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5*-4=-20 20*-1=-20 20-1=19 \[\frac{ 5x ^{2} -19x-4}{ x-4 }=\frac{ 5x ^{2} -\left( 20-1 \right)x-4}{ x-4 }=\frac{ 5x ^{2}-20x+1x-4 }{ x-4 }\] calculate the factors of the numerator and cancel the common factor.
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