Question

3x^2=-8x-2

Answer 1

Just need some help getting it to =0

Answer 2

3^2+8x+2=0 ?

Answer 3

ok, will work it and see if I come up with the right answer...

Answer 4

nope, getting - in the square root...

Answer 5

\[3x ^{2}=-8x -2\]
\[3x ^{2}+8x =-2\] - We added 8x to each side
\[3x ^{2}+8x +2=0\] We added 2 to each side

Answer 6

This is a trinomial that will need to be factored to solve for x.

Answer 7

factored, so the quadratic formula will not work?

Answer 8

product = 6
but sum = 8

if u cant find one, use quadratic formula, which is \( \pm \frac{-b \pm\sqrt{b^2-4ac}}{2a}\) where you have \(ax^2+bx+c=0\)

Answer 9

Yes, you will need to use the quadratic formula for this.

Answer 10

I'm getting -8 +/- square root -24 divide by 6

Answer 11

Where,
A=3
B=8
C=2

B^2 is 63, 4AC is 4(3)(2) or 24, so 64-24 is 40
You should have "40" under the radical.

Answer 12

Sorry, b^2 is 64, not 63

Answer 13

got it, thank you! simple error on my part.