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Calculus1
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integrate x ^(-7) dx
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use the standard result \(\huge \int x^ndx = \dfrac{x^{n+1}}{n+1}+c\)
here, n = -7
-(1/6) x^-6
correct :)
but isn't it if you integrate 1/x = ln|x|?
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a little confused because the original problem can be written as 1/x^7
it can be written, but to be able to use standard formula, you'll have to write 1/x^7 as x^-7 again :)
ok
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