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Use the substitution method to solve the following system of equations. 3x + 5y = 3 x + 2y = 0 A. (1, 1) B. (6, –3) C. (6, 1) D. (1, –3)
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First solve for x in the 2nd equation by subtracting 2y on both sides of the equation x + 2y = 0 x = -2y
Now substitute what x equals in the 1st equation 3x + 5y = 3 3(-2y) + 5y = 3 -6y + 5y = 3 -y = 3 y = -3
B.?
Correct :)
No.
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Thank you!
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Lol too funny :P No problemo! :)
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