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sketch a graph of y=f(x) f(x)=-2x+4
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since we have -2 as our slope the rise will be 2 while the run would be 1 as shown:|dw:1374466878365:dw| since +4 is our y-int it must cross the y axis at +4
plus its \[\frac{rise}{run}=\frac{-2}{1}\]
sso when i plot them would i be plotting all three
you only plot the equation you are given. the direction of the line is determined by the "sign" and value of the slope
you can plot any point to your choosing as long as it has a slope of -2 and crosses the y axis at +4!
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and nincompoop isnt b the y-int?
yes, that's the y-intercept I see I missed it
ok thanks i think i get it
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