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Mathematics 22 Online
OpenStudy (anonymous):

sketch a graph of y=f(x) f(x)=-2x+4

OpenStudy (anonymous):

since we have -2 as our slope the rise will be 2 while the run would be 1 as shown:|dw:1374466878365:dw| since +4 is our y-int it must cross the y axis at +4

OpenStudy (anonymous):

plus its \[\frac{rise}{run}=\frac{-2}{1}\]

OpenStudy (anonymous):

sso when i plot them would i be plotting all three

OpenStudy (nincompoop):

you only plot the equation you are given. the direction of the line is determined by the "sign" and value of the slope

OpenStudy (anonymous):

you can plot any point to your choosing as long as it has a slope of -2 and crosses the y axis at +4!

OpenStudy (anonymous):

and nincompoop isnt b the y-int?

OpenStudy (nincompoop):

yes, that's the y-intercept I see I missed it

OpenStudy (anonymous):

ok thanks i think i get it

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