hj
Hey, your first one is correct! The second one is not far off, you just need to check your minus/plus signs :)
@sarahusher okay so that's it? how do you combine like terms though with these problems? Oh this question never was copied into the box but is this one correct? 3. (x2 + 4x – 3)(2x2 + x + 6)x^2 ⋅ 2x^2= 2x^4 x^2 ⋅ 2x^2= x^2 x^2 ⋅ 6= 6x^2 4x ⋅ 2x^2= 8x^3 4x ⋅ x= 4x 4x ⋅ 6= 24x -3 ⋅ 2x^2= -6x^2 -3 ⋅ x+ -1 -1 ⋅ 6= -18 So,(x2 + 4x – 3)(2x2 + x + 6)= 2x^4 + x^2 + 6x^2 + 8x^3 + 4x + 24x – 6x^2 – 3 – 18 Standard form: 2x^4 + 8x^3 + 6x^2 + x^2 + x^2 + 24x – 18 – 6x^2 + 4x – 3 - 18
Okay the rules for combining terms is as follows: [It's very simple so don't worry] basically, you can combine terms that have the same power; for example; \[3x + 5x = (3+5)x = 8x\] or \[7x ^{2} + 26x ^{2} = (7+26)x ^{2} = 33x ^{2}\] However you cannot combine terms that have different powers, such as \[9x + 3x^{2}\] cannot be combined Do you understand?
and you need to recheck your answer, you're missing a few terms :)
@sarahusher ohhh thank you!! :) & okay :) thanks again
You are very welcome! Anytime I can be of help, just give me a message and I'll do my best to get back to you as soon as possible!
@sarahusher omg thank you!!
Also, sorry, you need to make sure you are fully multiplying out your brackets; which will be why you are missing some terms; so \[(a+b)\times(c+d+e) = ac+ad+ae+bc+bd+be\]
1. Correct 2. Wrong (4x – 3)(2x2 – 7x + 1) (4x.2x2-4x.7x+4x.1-3.2x2+3.7x-3.1) 8x3-28x2+4x-6x2-21x-3 8x3-34x2-17x-3
(x2 + 4x – 3)(2x2 + x + 6) x^2 ⋅ 2x^2= x^2 x^2 ⋅ 6= 6x^2 4x ⋅ 2x^2= 8x^3 4x ⋅ x= 4x 4x ⋅ 6= 24x -3 ⋅ 2x^2= -6x^2 -3 ⋅ x+ -1 -1 ⋅ 6= -18 So,(x2 + 4x – 3)(2x2 + x + 6)= 2x^4 + x^2 + 6x^2 + 8x^3 + 4x + 24x – 6x^2 – 3 – 18 Standard form: 2x^4 + 8x^3 + 6x^2 + x^2 + x^2 + 24x – 18 – 6x^2 + 4x – 3 - 18 @sarahusher is this correct? :)
Unfortunately, no x_x Some of your multiplication got you incorrect answers above and you even skipped a thing or two it seems. Here, I'll multiply it out. x^2 * 2x^2 = 2x^4 x^2 * x = x^3 x^2 * 6 = 6x^2 4x * 2x^2 = 8x^3 4x * x = 4x^2 4x * 6 = 24x -3 * 2x^2 = -6x^2 -3 * x = -3x -3 * 6 = -18 So now if you combine what you possibly can, you get 2x^4 + 9x^3 + 4x^2 + 21x - 18
you have the correct powers, but a little bit off on your coefficients, re check the \[8x ^{3}\] also you can combine your \[x^{2} \] functions when do you have to have this submitted by?
@sarahusher it doesn't really matter as long as I enter in assignments everyday.. I've been trying with these problems for a while & thats what i came up with lol
Okay, I think @psymon has given a very good explanation above, as to where you went wrong, if you have any trouble following this just let me know? :)
Join our real-time social learning platform and learn together with your friends!