PLEASE HELPPPPPPPP What is the axis of symmetry for y = x^2 - 8x + 8?
Do you know how to find the vertex of a quadratic function such as this? ^_^
no. i don't . i do on a graph
Oh, well, in that case, you can use a formula... the vertex for a quadratic equation of the form \[\Large y = \color{red}ax^2+\color{blue}bx+\color{green}c\]is \[\Large \left(-\frac{\color{blue}b}{2\color{red}a}\qquad , \qquad\frac{4\color{red}a\color{green}c-\color{blue}b^2}{4\color{red}a}\right)\]
But the axis of symmetry is just the line \[\huge x = -\frac{\color{blue}b}{2\color{red}a}\]
so is it -8/x^2
-b ----- will give you your x value for the turning point and x= bla is your 2a axis of symmetry :D
so x=4
what about this one ? What is the axis of symmetry for y = 4x^2 + 12x + 9?
use the formula -b/2a -> -12/8 = 3/2
its wrong
nvm Your forgot the -
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