Which of the following side lengths do NOT form a right triangle? A. 5 cm, 12 cm and 13 cm B. 8 cm, 15 cm and 17 cm C. 9 in, 40 in and 41 in D. 20 in, 21 in and 28 in
follow this guideline: a+b>c b+c>a a+c>b
but for a right triangle, you would test the pythagorean method
a^2+b^2=c^2 This is the Pythagorean theorem. Can you figure that out for me?
should i try out all the angles ? @Jamierox4ev3r
it would be good so that you can make sure your answer is correct
mention my name when you have the answer
D. Does 20^2+21^2=28^2 400 + 441 = 841 and 28^2=784 No, not a right triangle @Jamierox4ev3r
in this case, after you proved that, A. is the correct answer because of the following: 5^2+12^2=169 the square root of 169=13 Therefore, 5^2+12^2=13^2
Does that make sense?
not really @Jamierox4ev3r
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5^2=25 12^2=144 144+25=169 169=13^2 Therefore, 12^2+5^2=13^2
all of this proves that the above triangle is a right triangle indeed
so i can but A for the answer @Jamierox4ev3r
A. Does 5^2+12^2=13^2 25 + 144 = 169 and 13^2=169 Yes, right triangle B. Does 8^2+15^2=17^2 64 + 225 = 289 and 17^2=28 Yes, right triangle C. Does 9^2+40^2=41^2 81 + 1600 = 1681 and 41^2=1681 Yes, right triangle D. Does 20^2+21^2=28^2 400 + 441 = 841 and 28^2=784 No, not a right triangle @Jamierox4ev3r
oh idk what i was thinking for some if you are talking which is not a right triangle, the answer would be D. lol sorry
im slacking off srry :)) and thank you for pointing out my mistake
thanks yay ! (: @Jamierox4ev3r
anytime just keep up the great work and DFTBA (don't forget to be awesome)!
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