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Please help! Look at the figure. If tan x ̊= z divided by 10 and cos x ̊=10 divided by y ,what is the value of sin x°?
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tanx = [sinx/cosx] Put value from the the given data
So z/10=sinx/10/y ? Im lost.
Yes go ahead. You are doing right
z/10 =\[z/10=\sin \div 10/y\]
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OK z/10=y(sinx)/10 10 cancels out on both sides
z=sin/y
no its z=y sin(x)
\[\large \tan x=\frac{\sin x}{\cos x} \qquad\rightarrow\qquad \frac{z}{10}=\frac{\sin x}{\left(\dfrac{10}{y}\right)}\] Remember what happens when you divide by a fraction? You can rewrite it as multiplication by flipping the bottom fraction.\[\large \frac{z}{10}=\sin x \left(\frac{y}{10}\right)\] Just wanted to point that out, in case there was some confusion.
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