line P contains points A(-7,-9) and B(4,0). Line q is parallel to line p. Line r is perpendicular to line q. What is the slope of line r? Explain.
find slope of line p y-y x-x then take opposite reciprocal
\[\frac{ y-y }{ x-x }\]
If two lines are parallel, it means they have the same slope. That being said, P and Q each have the same slope. This also means that if r is perpendicular to q, then it is also perpendicular to p. A line has a perpendicular slope if its slope is the negative reciprocal of the other line. Slope is (y2 - y1)/(x2-x1) So for the line you have, you have a slope of (0-9)/(4-(-7)) = -9/11. So if P has a slope of -9/11, then a perpendicular slope has to be the negative reciprocal, meaning that the slope of r is 11/9
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