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Mathematics 15 Online
OpenStudy (anonymous):

For the triangle shown, find: a) Angle BCD b) Angle DCA

OpenStudy (anonymous):

OpenStudy (anonymous):

any other properties given to the triangles?

OpenStudy (anonymous):

Btw it's not a right triangle. That's all that is given.

OpenStudy (anonymous):

well you can use law of sines

OpenStudy (anonymous):

i think

OpenStudy (agent0smith):

Use the sine rule to find angle ADC, then angle DCA is easy to find (angles will add to 180).

OpenStudy (agent0smith):

sin30/20 = sin(ADC)/28

OpenStudy (anonymous):

I did use the sine rule but I sorta got stuck in the middle . . .

OpenStudy (anonymous):

oh wow . . . I was thinking wayyy to complicated then I needed . . . *facepalm* Thanks lol

OpenStudy (agent0smith):

To find BCD, find angle B first, you will use the same equation as above (it's the ambiguous case of the sine law). You can find angle BDC since BDA is a straight line, and so BDC and CDA will add to 180. Then after getting that, you can find BCD.

OpenStudy (anonymous):

Thanks a lot. I got it. ^^

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