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For the triangle shown, find: a) Angle BCD b) Angle DCA
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any other properties given to the triangles?
Btw it's not a right triangle. That's all that is given.
well you can use law of sines
i think
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Use the sine rule to find angle ADC, then angle DCA is easy to find (angles will add to 180).
sin30/20 = sin(ADC)/28
I did use the sine rule but I sorta got stuck in the middle . . .
oh wow . . . I was thinking wayyy to complicated then I needed . . . *facepalm* Thanks lol
To find BCD, find angle B first, you will use the same equation as above (it's the ambiguous case of the sine law). You can find angle BDC since BDA is a straight line, and so BDC and CDA will add to 180. Then after getting that, you can find BCD.
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Thanks a lot. I got it. ^^
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