For the triangle shown, find:
a) Angle BCD
b) Angle DCA

Question

For the triangle shown, find:
a) Angle BCD
b) Angle DCA

anonymous · Answer

attachment

anonymous · Answer

any other properties given to the triangles?

anonymous · Answer

Btw it's not a right triangle. 
That's all that is given.

anonymous · Answer

well you can use 
law of sines

anonymous · Answer

i think

agent0smith · Answer

Use the sine rule to find angle ADC, then angle DCA is easy to find (angles will add to 180).

agent0smith · Answer

sin30/20 = sin(ADC)/28

anonymous · Answer

I did use the sine rule but I sorta got stuck in the middle . . .

anonymous · Answer

oh wow . . . I was thinking wayyy to complicated then I needed . . . *facepalm* Thanks lol

agent0smith · Answer

To find BCD, find angle B first, you will use the same equation as above (it's the ambiguous case of the sine law).

You can find angle BDC since BDA is a straight line, and so BDC and CDA will add to 180. Then after getting that, you can find BCD.

anonymous · Answer

Thanks a lot. I got it. ^^