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OpenStudy (anonymous):
Find the area of the following figure
12 years ago
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OpenStudy (anonymous):
12 years ago
OpenStudy (mayankdevnani):
this quadrilateral is TRAPEZIUM
12 years ago
OpenStudy (anonymous):
who cares
12 years ago
OpenStudy (mayankdevnani):
\[\huge area~of~trapezium=h(\frac{a+b}{2})\]
where h=height of trapezium,
a and b are opposite sides of trpaeziumm or parallel sides
12 years ago
OpenStudy (mayankdevnani):
can you find the area ? @Absoluter
12 years ago
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OpenStudy (anonymous):
@absoluter just say you don't understand, many times, this should usually just get you the answer
12 years ago
OpenStudy (anonymous):
is it 24
12 years ago
OpenStudy (anonymous):
or 40
12 years ago
OpenStudy (mayankdevnani):
yes... 40 is correct answer
12 years ago
OpenStudy (anonymous):
i got more questions can you help me?
12 years ago
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OpenStudy (anonymous):
thanks
12 years ago
OpenStudy (mayankdevnani):
\[\huge area=4(\frac{8+12}{2})\]
\[\huge 4(\frac{20}{2})\]
\[\huge 4 \times 10= \color{red}{40}\]
12 years ago
OpenStudy (mayankdevnani):
welcome :) @Absoluter
12 years ago
OpenStudy (anonymous):
very informative
12 years ago
OpenStudy (mayankdevnani):
oh!
12 years ago
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OpenStudy (anonymous):
i got another question
?'
12 years ago
OpenStudy (mayankdevnani):
@Absoluter i have to go now.... i will get back on tomorrow
sorry for that... Just post your question. i think JACK will tell you ..
or anyone tell you..
i hope you understand with my all answers.
12 years ago
OpenStudy (anonymous):
i do thanks
12 years ago
OpenStudy (mayankdevnani):
welcome :)
and again sorry :(
12 years ago
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