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find all roots of z^5-1-j=0 and plot on a complex plane what is even the working to this?
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Whats is j? General quintic equations can't be solved in terms of elementary functions.
j is the square root of -1 i should get into the habit of typing it as i actually
lol your used to using i to denote current?
yeah my uni has very unorthodox way of teaching
Here are all 5 solutions, along with an argand diagram plotting them
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\[z^5-1-i=0\]\[z^5=1+i=\sqrt{2}\left(\frac{1}{\sqrt{2}}+\frac{1}{\sqrt{2}}i\right)=\sqrt{2}\exp\left(\frac{\pi}{4}+2\pi k\right),k=0,\dots,4\]\[z=\sqrt[10]{2}\exp\left(\frac{\pi}{20}+\frac{2\pi}{5} k\right),k=0,\dots,4\]
I dont understand your question Loser66.
never mind, I got it. thanks for response
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