Question

x^2+12x+36=0

Answer 1

factor it out:
\[(x + 6)^2 = 0\]
\[x+6 = 0\]
\[x = -6\]
both factors are the same, so \[x _{1/2} = -6\]

Answer 2

what about (x+8)(x+8)=0 @Kiro

Answer 3

same, both terms are the same (x+8) so they give the same answer, consider each to be = 0, so you get \[x+8 = 0\]\[x=-8\]
So, \[x _{1/2}=-8\]
If you had two different terms in parentheses, and 2 different radicals, respectfully.

Answer 4

and if it was the opposite (x-8)(x-8)

Answer 5

would it be 8

Answer 6

@Kiro

Answer 7

Yes, exactly, just solve the linear equation for each term, if they are the same, just solve for one of them and you're good ;)

Answer 8

x^2-10x+25
would it be 5 or negative five @Kiro

Answer 9

=0

Answer 10

factor it and you will see, I trust that you know how to factor a quadratic equation?