Mathematics
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OpenStudy (anonymous):
x^2-10x+25=0
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terenzreignz (terenzreignz):
It would seem the most efficient way to solve this is via factoring :)
OpenStudy (anonymous):
would the answer be 5
OpenStudy (anonymous):
-5 * -5= 25
-5 - 5 = -10
OpenStudy (anonymous):
(x-5)^2 via factoring
terenzreignz (terenzreignz):
An easy way to tell, @ortizgiovanni21
substitute 5 for x in the equation, and see if it becomes 0 :P
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OpenStudy (anonymous):
x^2-5x-5x+25
=x(x-5)+5(x-5)
=(x-5)(x+5)
OpenStudy (anonymous):
so factors out to be (x - 5)(x - 5) or what @oxford422 wrote
OpenStudy (anonymous):
The answer is 5 double root
OpenStudy (anonymous):
so the solution set it 5
OpenStudy (anonymous):
double root or D. R. is important though because it shows that there were two 5s not only one
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OpenStudy (anonymous):
so it is positive 5
OpenStudy (anonymous):
it would look like 5 D.R.
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
x^2+6x+9=0
would it be 3 or negative 3
OpenStudy (anonymous):
@FriedRice
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OpenStudy (anonymous):
yes @ortizgiovanni21
OpenStudy (anonymous):
again it would be 3 D. R. if you dont include D. R. it is wrong
OpenStudy (anonymous):
it will be 3
OpenStudy (anonymous):
@FriedRice do you not agree about the D. R.
OpenStudy (anonymous):
yes unless it is part of the answer
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OpenStudy (anonymous):
I mean multiple answer
OpenStudy (anonymous):
Im just trying to get ortizgiovani21 to understand that you need to note that there are two anwsers not just one
OpenStudy (anonymous):
or you can write x = 5, 5
OpenStudy (anonymous):
It doesn't matter unless it gives certain instructions
OpenStudy (anonymous):
true but to say the answer is 5 would be wrong
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OpenStudy (anonymous):
true that so you can write it like that and that is the correct form of writing the solution
OpenStudy (anonymous):
??
OpenStudy (anonymous):
x^2+8x+16=0 would that be -4
OpenStudy (anonymous):
4 or 4 D.R
OpenStudy (anonymous):
+4 D. R....not to be extremely obnoxious aboout the D. R.
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OpenStudy (anonymous):
4*4 is 16 and 4+4 is 8 so thats why